Complete the reaction and write the name of the product.
$C H_{3} C H_{2} O H A l_{2} O_{3} - -- \to 620 K$ ?

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Solution

Dehydration of ethanol in presence of ${A l}_{2} O_{3}$ gives ethene.
$C H_{3} C H_{2} O H {A l}_{2} O_{3} - -- \to 620 K C H_{2} = C H_{2} ethene$
Hence, in the given reaction, the product formed is ethene $(C_{2} H_{4})$ .

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