Complete the reaction:
$H C l + N a O H \to$

N a C l + H_{2} O

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N a C l + H + O H

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N a C l + H_{2}

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N a + C l + H_{2} O

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Solution

The correct option is D $N a C l + H_{2} O$
When hydrochloric acid $(H C l)$ and sodium hydroxide $(N a O H)$ react with each other, neutralization reaction takes place and there is the formation of salt (sodium chloride $N a C l$ ) and water.

The acid releases hydrogen ion $H^{+}$ which combines with the hydroxyl ion $(O H^{-})$ released by the base, to form water. The anion of the acid and cation of the base combine together to form the salt.

$H C l + N a O H \to N a C l + H_{2} O$

Thus, the answer correct is an option (A).

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Similar questions

H C l + H_{2} O \to H_{3} O^{+} + C l^{-}

H_{2} O + N_{3} \to O H^{-} + N H_{4}^{-}

H S^{-} + H C l \to C l^{-} + H_{2} S

H S^{-} + N H_{3} \to N H_{4}^{+} + S^{2 -}

H C l + N a O H \to N a C l + H_{2} O

N a C l + H_{2} O \to H C l + N a O H

N a O H + H C l ⟶ N a C l + H_{2} O

What type of chemical reaction is this?

NaOH + HCL --------> NaCl + H2O

H C l + N a O H \to N a C l + H_{2} O + x c a l .

H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O + y c a l

H C l + N a O H \to N a C l + H_{2} O

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