Question

Complete the relation in ratio given.
$\cos \theta =\sin (90-$__________$)$.

Answer 1

$\begin{array}{c}\cos \theta =\sin \left({90}^0-\theta \right)\\ \Rightarrow \frac{\cos \theta }{\sin \left({90}^0-\theta \right)}=1\\ \Rightarrow \frac{\cos \theta }{\cos \theta }=1Ans.\end{array}$