Question

Complete the relation in ratio given.
$\sin \theta =\cos (90-$___________$)$.

Answer 1

$\begin{array}{c}\sin \theta =\cos \left({90}^0.......\right)\\ \Rightarrow \frac{\sin \theta }{\cos \left({90}^0-\theta \right)}=1\\ \left[\because \cos \left({90}^0-\theta \right)=1\right]\\ \Rightarrow \frac{\sin \theta }{\sin \theta }=1Ans.\end{array}$