Question

Complete the relation in ratio given.
$\tan \theta x\tan (90-\theta )=$_________.

Answer 1

$\begin{array}{c}\tan \theta \cdot x\tan \left({90}^0-\theta \right)\\ \Rightarrow \tan \theta \cdot x\cdot \cot \theta =........\left[\tan \left({90}^0-\theta \right)=\cot \theta \right]\\ \Rightarrow \tan \theta \cdot \cot \theta =\frac{1}{x}\\ \Rightarrow \frac{\tan \theta }{\tan \theta }=\frac{1}{x}\\ \therefore 1=\frac{1}{x}Ans.\end{array}$