Complete the series by finding the missing pair of terms from the given alternatives.
1, 1, 1, 2, 4, 8, 3 ?, ?

6, 12

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9, 18

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18, 27

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9, 27

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Solution

The correct option is A 9, 27
The series forms groups of 3 numbers viz.
$(1, 1, 1) = (1^{1}, 1^{2}, 1^{3})$
$(2, 4, 8) = (2^{1}, 2^{2}, 2^{3})$
$(3, -, -) = (3^{1}, 3^{2}, 3^{3})$

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