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Question

Complex number z satisfying the equation z2×(1+i)=7+17i, is/are

A
z=3+2i
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B
z=3+2i
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C
z=32i
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D
z=32i
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Solution

The correct options are
B z=3+2i
C z=32i
z2×(1+i)=7+17i

Let z=x+iy, where x,yR
(x+iy)2=7+17i(1+i)x2y2+2ixy=10+24i2x2y2=5,2xy=12

Solving the equations, we get
x=3,y=2 or x=3,y=2

Hence z=3+2i or z=32i

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