Component of vector →A=3^i+2^j+^k perpendicular to vector →B=^i−2^j is
A
165^i+85^j+^k
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B
5^i+2^j+^k
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C
^k
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D
−35^i+25^j−^k
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Solution
The correct option is A165^i+85^j+^k →C=→A−Acosθ^B=→A−→A.→BB×→BB=→A−→A.→BB2→B →A.→B=3−4=−1, B=√5 →C=3^i+2^j+^k−(−1)5(^i−2^j)=3^i+2^j+k+^i5−25^j=165^i+85^j+k