Component of vector A -3 -2 -k- perpendicular to vector B -2 - isA- 16-5-8-5-k-B- 5 -2 -k-C- k-D- -3-5-2-5-k-

C = nbsp;A A cos θB̂ = A A. B/B×B/B = A A . B/B^2B nbsp; A . B = 3 4= 1, nbsp; nbsp; B = √(5) nbsp; C = 3 î + 2 ĵ + k̂ ( 1)/5 (î 2 ĵ) = 3 ...

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Vector Component

Component of ...

Question

Component of vector $\to A = 3^i + 2^j +^k$ perpendicular to vector $\to B =^i - 2^j$ is

\frac{16}{5}^i + \frac{8}{5}^j +^k

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5^i + 2^j +^k

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^k

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\frac{- 3}{5}^i + \frac{2}{5}^j -^k

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Solution

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Similar questions

\to A =^i + 2^j -^k

\to B = 2^i + 3^j + 4^k

\to A

\to B

\to A =^i - 2^j +^k

\to B = 3^i - 2^j -^k

\to a = 3^i + 2^j + 2^k

\to b =^i + 2^j - 2^k

\to a + \to b

\to a - \to b

12

The vector having initial and terminal points are (2, 5, 0) and (-3, 7, 4), respectively is

(a) $-^i + 12^j + 4^k$

(b) $5^i + 2^j - 4^k$

(d) $^i +^j +^k$

\to a = 2 \to i +^j +^k, \to b =^i + 2^j -^k

\to c

\to c

\to a,

\to c

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