Compound $A$ and $B$ respectively are:

o-Bromostyrene, benzoic acid

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p-Bromostyrene, benzaldehyde

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m-Bromostyrene, benzaldehyd

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styrene dibromide, benzoic acid

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Solution

The correct option is B styrene dibromide, benzoic acid
When styrene is brominated, styrene dibromide is obtained.
In this reaction a molecule of bromine is added across carbon-carbon double bond.

Oxidation of styrene with potassium permanganate gives benzoic acid.
In this reaction, the side chain is oxidized to carboxylic group.

Option D is correct.

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Similar questions

Give simple chemical tests to distinguish between the following pairs of compounds.

(i) Propanal and Propanone

(ii) Acetophenone and Benzophenone

(iii) Phenol and Benzoic acid

(iv) Benzoic acid and Ethyl benzoate

(v) Pentan-2-one and Pentan-3-one

(vi) Benzaldehyde and Acetophenone

(vii) Ethanal and Propanal

P h e n o l Z n d u s t - --- \to X C H_{3} C l - ------- \to A n h y d A l C l_{3} Y A l k K M n O_{4} - ------ \to Z

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