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Amino Acids

A. 1B. 2C. 3D...

Question

Compound $^{'} A^{'}$ has how many functional groups.

A

1

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B

2

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C

3

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D

4

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Solution

The correct option is C $3$
Compound A is nothing but serine. We know that serine is an acidic amino acid. It has an $- O H$ group on the side chain. Since it is an amino acid, the functional groups $- C O O H$ and $- N H_{2}$ are already present in it. Hence, there are a total of 3 functional groups present: $- O H, - C O O H, - N H_{2}$ .

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\int_{- 1}^{4} f (x) d x = 4

\int_{2}^{4} [3 - f (x)] d x = 7 t h e n \int_{- 1}^{2} f (x) d x =

I f I_{1} = \int_{0}^{1} 2^{x^{2}} d x, I_{2} = \int_{0}^{1} 2^{x^{3}} d x, I_{3} = \int_{1}^{2} 2^{x^{2}} d x a n d I_{4} = \int_{1}^{2} 2 x^{3} d x t h e n

\int_{- 1}^{4} f (x) d x = 4

\int_{2}^{4} [3 - f (x)] d x = 7

, then the value of

\int_{- 1}^{2} f (x) d x

I_{1} = \int_{0}^{1} 2^{x^{2}} d x

I_{2} = \int_{0}^{1} 2^{x^{3}} d x

I_{3} = \int_{1}^{2} 2^{x^{2}} d x

I_{4} = \int_{1}^{4} 2^{x^{3}} d x

then which of the following is true?

I_{1} = \int_{0}^{1} 2^{x^{2}} d x, I_{2} = \int_{0}^{1} 2^{x^{3}} d x, I_{3} = \int_{1}^{2} 2^{x^{2}} d x

I_{4} = \int_{1}^{2} 2^{x^{3}} d x

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