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Question

Compound (A) is a greenish crystalline salt which gives the following results when tested :

(a) Addition of BaCl2
solution to a solution of (A) results in the formation of a white precipitate (B) which is insoluble in dilute HCl.
(b) On heating, water vapour and two gases (C) and (D) are liberated, leaving a red brown residue (E).
(c) (E) dissolves in conc.HCl to give a yellow solution (F).
(d) With H2S,
the solution (F) yields a yellow-white ppt. (G) which when filtrated, leaves a greenish filtrate (H).
(e) The solution (F) gives a green solution with SnCl2, and when reacted with K4[Fe(CN)6]
gives a blue ppt.

Identify compound (A) :

A
ZnSO4.7H2O
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B
FeSO4.7H2O
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C
MgSO4.7H2O
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D
CuSO4.5H2O
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Solution

The correct option is B FeSO4.7H2O
(A) is FeSO47H2O
FeSO4+BaCl2BaSO4+FeCl2(B)
2FeSO4ΔFe2O3+SO2+SO3(E)(C)(D)
Fe2O3+6HCl2FeCl3+3H2O(F)
2FeCl3+H2S2FeCl2+2HCl+S(H)(G)
2FeCl3+SnCl22FeCl2+SnCl4
4FeCl3+3K4Fe(CN)6Fe4[Fe(CN)6]3+13KClPrussianBlue
(FeCl3 gives blood red coloration with thiocyanate ion.)
FeCl3+3KSCNFe(SCN)3+3KClPotassiumBloodredthiocyanatecoloration

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