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Question

Compound A is a light-green crystalline solid. It gives the following tests :

(i) It dissolves in dilute sulphuric acid. No gas is produced.

(ii) A drop of KMnO4 is added to the above solution. The pink color disappears.

(iii) Compound A is heated strongly. Gases B and C, with a pungent smell, come out. A brown residue D is left behind.

(iv) The gas mixture (B and C) is passed into a dichromate solution. The solution turns green. But when only C is passed no change occurs.

(v) The green solution from step (iv) gives a white precipitate E with a solution of barium nitrate.

(vi) Residue D from step (iii) is heated on charcoal in a reducing flame. It gives a magnetic substance.

Thus, name the compound A is______ .

A
Fe(NO3)2
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B
Cr2(SO4)3
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C
FeSO4
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D
Fe2(SO4)3
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Solution

The correct option is C FeSO4
A light-green crystalline solid is expected to be ferrous sulphate.
There is no reaction with dilute sulphuric acid. With potassium permanganate, ferrous sulphate is oxidized to ferric sulphate and the pink colour disappears.
On strong heating, it gives two gases which are two oxides of sulphur, along with a brown residue, ferric oxide.
When gases are passed through acidified potassium dichromate, it is reduced by sulphur dioxide to give a green solution of chromium sulphate.
On adding barium sulphate, the green solution of sulphate gives a white precipitate of barium sulphate.
In charcoal cavity test, ferric oxide is reduced to iron which is magnetic.

FeSO4+dilNoreaction

FeSO4+KMnO4H2SO4−−−Fe2(SO4)3+Mn2+(Pink)(Colorless)
FeSO4ΔFe2O3+SO2+SO3
K2Cr2O7+SO2H2SO4−−−Cr2(SO4)3Green
H2O+SO3H2SO4
H2SO4+Ba(NO3)22HNO3+BaSO4White

Therefore, C is correct option.

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