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Standard XII

Chemistry

Chemical Properties of Alcohol

Compound A of...

Question

Compound A of molecular formula $C_{3} H_{6} O$ does not reduce not reduce Tollen's reagent nod Fehling's solution. Compound A undergoes Clemmensen reduction to give compound B of molecular formula $C_{3} H_{8}$ . Compound A in the presence of Conc. $H_{2} S O_{4}$ condenses is give air aromatic compound C of molecular formula $C_{9} H_{12}$ .
Identify B and C. Explain the reactions.

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Solution

$C_{3} H_{6} O$ must be ketone(acetone) because Tollen's reagent and Fehling's reagents are not reducing it.
Acetone on reaction with distilled water and concentrated $H_{2} S O_{4}$ gives Mesitylene $(C) - C_{9} H_{12}$ which is aromatic.

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C3H6O must be ketone(acetone) because Tollen's reagent and Fehling's reagents are not reducing it.Acetone on reaction with distilled water and concentrated H2SO4 gives Mesitylene (C)−C9H12 which is aromatic.

$C_{3} H_{6} O$ must be ketone(acetone) because Tollen's reagent and Fehling's reagents are not reducing it.
Acetone on reaction with distilled water and concentrated $H_{2} S O_{4}$ gives Mesitylene $(C) - C_{9} H_{12}$ which is aromatic.