Compound A reacts with HCl to yield a gas B that turns limewater milky. Compound X reacts with HCl to evolve a gas Y with odour of a burning matchstick. Choose the option depicting the correct set of compounds A, B, X, and Z.

C a C O_{3}

, B:

C O_{2}

,
X:

N a_{2} S O_{3}

, Y:

H_{2}

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C a C O_{3}

, B:

C O_{2}

,
X:

N a_{2} S O_{3}

, Y:

S O_{2}

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C u C O_{3}

, B:

H_{2}

,
X:

N a_{2} S O_{3}

, Y:

C O_{2}

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C u C O_{3}

, B:

C O_{2}

,
X:

N a_{2} S O_{3}

, Y:

S O_{2}

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Solution

The correct option is B A: $C a C O_{3}$ , B: $C O_{2}$ ,
X: $N a_{2} S O_{3}$ , Y: $S O_{2}$

In the question it is mentioned that the gas B turns the lime water milky. So, the gas is $C O_{2}$ .

When metal carbonate reacts with it gives $C O_{2}$ .

Thus this metal can not be copper but it can be calcium.

In the question it is mentioned that the gas Y has the odour of burning matchstick. So, the gas is $S O_{2}$ .

when metal sulphite reacts with it gives $S O_{2}$ .

So compound X is $N a_{2} S O_{3}$ .

A is $C a C O_{3}$ ,B is $C O_{2}$ , X is $N a_{2} S O_{3}$ and Y is $S O_{2}$ .

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