Compound $A$ undergoes following reactions to form $B$ and $C$ . $(C)$ gets decolorised by $F e^{3 +}$ . Identify $A, B$ and $C$ respectively.

Black coloured solid $(A) K N O_{3} + K O H - ---------------- \to G r e e n c o l o u r e d s o l u t i o n (B)$ Green Coloured Solution $(B)$
$C O_{2} - - \to$ Pink solution $(C) + (A)$ .

M n O_{2}, K M n O_{4}

and

K_{2} M n O_{4}

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M n O_{2}, K_{2} M n O_{4}

and

K M n O_{4}

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K M n O_{4}, M n O_{2}

and

K_{2} M n O_{4}

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K M n O_{4}, K_{2} M n O_{2}

and

M n O_{2}

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Solution

The correct option is B $M n O_{2}, K_{2} M n O_{4}$ and $K M n O_{4}$
$M n O_{2} (B l a c k) A + 2 K O H + K N O_{3} Δ - \to K_{2} M n O_{4} G r e e n + K N O_{2} + H_{2} O$

$C O_{2} + H_{2} O ⇌ H_{2} C O_{3} ⇌ H^{+} + H C O_{3}^{-}$

$3 M n O_{4}^{2 -} B + 4 H^{+} \to M n O_{2} A + 2 M n O_{4}^{-} C + 2 H_{2} O$

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Compound A undergoes following reactions to form B and C. (C) gets decolorised by Fe3+. Identify A,B and C respectively.Black coloured solid (A)KNO3+KOH−−−−−−−−−−−−−−−−−→Green coloured solution (B) Green Coloured Solution (B)CO2−−→ Pink solution (C)+(A).

The correct option is B MnO2,K2MnO4 and KMnO4MnO2(Black)A+2KOH+KNO3Δ−→K2MnO4Green+KNO2+H2OCO2+H2O⇌H2CO3⇌H++HCO−33MnO2−4B+4H+→MnO2A+2MnO−4C+2H2O