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Question

Compound C8H9Cl (A) on treatment with KCN followed by hydrolysis gives C9H10O2 (B). Ammonium salt of (B) on dry distillation gives (C), which reacts with alkaline solution of bromine to give C8H11N (D). Another compound (E), is obtained by the action of nitrous acid on (D) or by the action of aqueous potash on (A). (E) on oxidation gives C8H6O4 (F) which gives an anhydride C8H4O3 (G) on heating.

If x is the DOE of (G) and y is the DOE of (F), then x-y=

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Solution

Since the ratio of carbon to hydrogen in (A) is almost 1:1, it should be benzenoid.

Since (A) reacts with KCN, it should have either a CH2Cl or a CH2CH2Cl group. The reacon as to why CH2CH2Cl is not the required substituent because later we get an anhydride which means that a methyl group should be oxidised to carboxylic acid.


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