Compound E on long standing slowly converts into yellow, brown, and finally black to the formation of :

H g_{2} S

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A g_{2} S

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H g S

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H g (N H_{2}) C l + H g

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Solution

The correct option is B $A g_{2} S$
White precipitate changes to yellow, brown and finally becomes black
$S_{2} O_{3}^{2 -} + 2 A g^{+} \to A g_{2} S_{2} O_{3} w h i t e; A g_{2} S_{2} O_{3} + H_{2} O \to A g_{2} S b l a c k + H_{2} S O_{4}$
$2 A g N O_{3} 450^{o} C - -- \to 2 A g + 2 N O_{2} + O_{2}$
$A g^{+} + 2 C N^{-} \to [A g (C N)_{2}]^{-} + I^{-}$

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x

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