Compound (P) forms a precipitate with $A g N O_{3} .$ The precipitate dissolves in excess reagent (P). (P) can not be :

K O H

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K C N

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N a_{2} S_{2} O_{3}

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N H_{3}

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Solution

The correct option is A $K O H$
$(1) 2 A g N O_{3} + 2 K O H \to A g_{2} O (b l a c k) + 2 K N O_{3} + H_{2} O$
excess KOH
no reaction
$(2) A g N O_{3} C N^{-} \to A g C N (w h i t e) C N^{-} - --- \to e x c e s s A g (C N)_{2}^{-}$
(soluble)
(3) $A g N O_{3} S_{2} O_{3}^{2 -} \to A g_{2} S_{2} O_{3} (w h i t e) S_{2} O_{3}^{2 -} - --- \to e x c e s s$ $A g (S_{2} O_{3})_{2}^{3 -} (s o l u b l e)$

(4) $A g N O_{3} N H_{3} \to A g_{2} O (b l a c k) N H_{3} - --- \to e x c e s s [A g (N H_{3})_{2}]^{+}$
(soluble)
Hence, (2), (3) & (4) are not the answers.

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Similar questions

Q. Which of the following hydrogen halides react(s) with

A g N O_{3}

(aq) to give a precipitate that dissolves in

N a_{2} S_{2} O_{3}

(aq)?

Q. Which of the following cations (i.e., basic radicals) forms colored (not white) precipitate with aqueous solution of potassium iodide but the precipitate does not dissolve in excess of reagent ?

Q. When excess of

N a_{2} S_{2} O_{3}

is added to dil.

A g N O_{3}

, a soluble compound ‘X’ is formed. However, when dil.

N a_{2} S_{2} O_{3}

is added to conc.

A g N O_{3}

solution, a white precipitate turns yellow and finally black. Precipitate ‘Y’ is formed here. Which is the correct pair?

Q. Match the Following:

\begin{matrix} C o l u m n I & C o l u m n I I (a) & C u C l_{2} + N a_{2} S_{2} O_{3} & (p) & M e t a l i o n a c t s a s a n o x i d i z i n g a g e n t . (b) & A g B r + N a_{2} S_{2} O_{3} & (q) & F o r m a t i o n o f t e t r a t h i o n a t e a n i o n (c) & A u C l_{3} + N a_{2} S_{2} O_{3} & (r) & D i s s o l v e s i n e x c e s s o f N a_{2} S_{2} O_{3} s o l u t i o n d u e t o c o m p l e x f o r m a t i o n (d) & B a C l_{2} + N a_{2} S_{2} O_{3} & (s) & P r e c i p i t a t e f o r m e d d o e s n o t d i s s o l v e i n e x c e s s o f N a_{2} S_{2} O_{3} \end{matrix}

This question and the next one appeared in the in the linked comprehension format. Let's give them a shot.

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:
SCHEME:

M1, Q and R, respectively are

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Compound (P) forms a precipitate with AgNO3. The precipitate dissolves in excess reagent (P). (P) can not be :

Compound (P) forms a precipitate with $A g N O_{3} .$ The precipitate dissolves in excess reagent (P). (P) can not be :