Compound PdCl4.6H2O is a hydrated complex. Its 1 molal aqueous solution has a freezing point of 269.28 K. Assuming 100% ionization of the complex, calculate the molecular formula of the complex. (Kf for water =1.86 Kkgmol−1)
A
[Pd(H2O)6]Cl4
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B
[Pd(H2O)4Cl2]Cl2.2H2O
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C
[Pd(H2O)3Cl3]Cl.3H2O
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D
[Pd(H2O)2Cl4].4H2O
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Solution
The correct option is C[Pd(H2O)3Cl3]Cl.3H2O ΔTf=273−269.28=3.87K 3.72=iKfm=i×86×1 ∴i=2 Looking at the options, only option c produces 2 ions in solutiohn - one complex ion and the other - chloride ion.