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Question

Compound that is both paramagnetic and coloured is:

A
K2Cr2O7
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B
(NH4)2[TiCI6]
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C
VOSO4
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D
K3[Cu(CN)4]
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Solution

The correct option is D VOSO4
In VOSO4 we have no VO+ ion in which oxidation state of V is +3.
So, the electronic configuration for V3+ is [Ar] 3d24s0 because of presence of 2 unpaired es it is paramagnetic and coloured as well.
K2Cr2O7 - diamagnetic -orange
(NH4)2[TiCl6]- diamagnetic - colourless
K3[Cu(CN)4] - diamagnetic- colourless.

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