The correct option is D K, L
In compound (X), the Cl− group leaves to form a secondary carbocation followed by attack of OH− to give compound (K).
Also, the secondary carbocation formed from (X) undergoes 1, 2 Hydride-shift to form a stable carbocation followed by attack of OH− to give compound (L). Formed carbocation is also stabilised by electron donating group −OCH3. This will be the major product of the reaction.
Secondary carbocation formed does not undergoes 1, 2-methyl shift to give compound (M) because NO2 is electron withdrawing group so it will destabilize the carbocation.
Hence, option (a) is the correct answer.