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Borax

Compound X ...

Question

Compound $(X)$ on reduction with $L i A l H_{4}$ gives a hydride $(Y)$ containing 21.72% hydrogen along with other products. The compound $(Y)$ react with air explosively resulting in boron trioxide. Compounds $X$ and $Y$ are respectively:

A

B C l_{3}, B_{2} H_{6}

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B

B_{2} H_{6}, B C l_{3}

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C

B F_{3}, A l_{2} O_{6}

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D

B_{2} H_{6}, B F_{3}

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Solution

The correct option is C $B C l_{3}, B_{2} H_{6}$
$(A)$ $B {C l}_{3}, B_{2} H_{6}$
Since $B_{2} O_{3}$ is formed by reaction of $(Y)$ with air, $(Y)$ therefore should be $B_{2} H_{6}$ in which % of hydrogen is 21.72.
$B_{2} H_{6} + 3 O_{2} ⟶ B_{2} O_{6} + 3 H_{2} O + h e a t$
The compound $(X)$ on reduction with $L i A I H_{4}$ gives $B_{2} H_{6}$ . Thus it is boron trihalide.
$4 B X_{3} + 3 L i A l H_{4} ⟶ 2 B_{2} H_{6} + 3 L i X + 3 A l X_{3}$ ( $X = C I$ or $B r$ )

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Similar questions

Q. Compound X on reduction with

L i A l H_{4}

gives a hydride Y containing 21.72% hydrogen and other products. The compound Y reacts explosively with air resulting in the formation of Boron Trioxide. What are X and Y ,respectively?

X

on reduction with

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gives a hydride

Y

21.72

% hydrogen along with other products. The compound

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, of boron reacts with

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Q. A compound of boron X reacts at

200^{\circ} C

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