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Question

Compound (X) on reduction with LiAlH4 gives a hydride (Y) containing 21.72% hydrogen along with other products. The compound (Y) react with air explosively resulting in boron trioxide. Compounds X and Y are respectively:

A
BCl3,B2H6
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B
B2H6,BCl3
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C
BF3,Al2O6
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D
B2H6,BF3
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Solution

The correct option is C BCl3,B2H6
(A) BCl3,B2H6
Since B2O3 is formed by reaction of (Y) with air, (Y) therefore should be B2H6 in which % of hydrogen is 21.72.
B2H6+3O2B2O6+3H2O+heat
The compound (X) on reduction with LiAIH4 gives B2H6. Thus it is boron trihalide.
4BX3+3LiAlH42B2H6+3LiX+3AlX3 (X=CI or Br)

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