Compound X shows the following reaction:
$(X) H^{+} - --- \to - H_{2} O [Y^{\oplus}]$
$Y^{+}$ is a highly stable smallest cyclic cation. It's all H atoms are identical in nature. The general formula of X is $C_{x} H_{y} O$ . Calculate molecular weight of X. (Report your answer as $\frac{X}{7}$ )

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Solution

Compound $X$ is cycloprop-2-enol. In presence of acid, it loses hydroxide group to form cycloprop-2-en-1-ylium. The molecular formula of $X$ is $C_{3} H_{4} O$ . The molecular weight of X is $(3 \times 12) + (4 \times 1) + 16 = 36 + 4 + 16 = 56$ . Hence, the molecular weight of $X$ is 56g/mol.

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Compound X shows the following reaction:(X)H+−−−−→−H2O[Y⊕]Y+ is a highly stable smallest cyclic cation. It's all H atoms are identical in nature. The general formula of X is CxHyO. Calculate molecular weight of X. (Report your answer as X7)

Compound X is cycloprop-2-enol. In presence of acid, it loses hydroxide group to form cycloprop-2-en-1-ylium. The molecular formula of X is C3H4O. The molecular weight of X is (3×12)+(4×1)+16=36+4+16=56. Hence, the molecular weight of X is 56g/mol.

Compound X shows the following reaction:
$(X) H^{+} - --- \to - H_{2} O [Y^{\oplus}]$
$Y^{+}$ is a highly stable smallest cyclic cation. It's all H atoms are identical in nature. The general formula of X is $C_{x} H_{y} O$ . Calculate molecular weight of X. (Report your answer as $\frac{X}{7}$ )

Compound $X$ is cycloprop-2-enol. In presence of acid, it loses hydroxide group to form cycloprop-2-en-1-ylium. The molecular formula of $X$ is $C_{3} H_{4} O$ . The molecular weight of X is $(3 \times 12) + (4 \times 1) + 16 = 36 + 4 + 16 = 56$ . Hence, the molecular weight of $X$ is 56g/mol.