Question

Compounds formed by $s{p}^3{d}^2$-hybridization will have which of the following geometry ?

• A. square planar
• B. octahedral
• C. trigonal bipyramidal
• D. pentagonal bipyramidal

Answer 1

Answer: (A), (B)

The correct options are
A square planar
B octahedral

Consider the hybridizations for the shapes mentioned below:-
A) Square Planar- $s{p}^3{d}^2$ with 2 lone pairs.
B) Octahedral - $s{p}^3{d}^2$ with no lone pairs.
C) Trigonal Bipyramidal- $s{p}^{3}d$ with no lone pairs.
D) Pentagonal Bipyramidal- $s{p}^3{d}^3$.
Hence option A or B is the right answer.