Compressibility factor under critical state of a gas is:

\frac{5}{8}

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\frac{8}{3}

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\frac{3}{8 R}

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\frac{3}{8}

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Solution

The correct option is D $\frac{3}{8}$
(D) $\frac{3}{8}$
Since $\frac{R T_{c}}{P_{c} V_{c}} = \frac{8}{3}$
$∴ z = \frac{P_{c} V_{c}}{R T_{c}} = \frac{3}{8}$ (at critical conditions).

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Similar questions

P_{c}, V_{c}, T_{c}

\frac{a}{27 b^{2}}, 3 b

\frac{8 a}{27 R b}

Z

\frac{3}{8}

List-I	List-II
(a) The highest temperature at which liquid $C O_{2}$ exists	(p) $\frac{V_{r e a l}}{V_{i d e a l}}$
(b) 8a / 27 Rb	(q) Critical temperature
(c) Compressibility factor Z = 3/8 at	(r) Ideal gas
(d) Compressibility factor Z = 1 for	(s) ${30.98}^{o} C$

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