Compressibility of water is $5 \times 10^{- 10} m^{2} / N .$ Find the decrease in volume of 100 mL of water when subjected to a pressure of 15 MPa.

= - 0.75 m L

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= - 0.85 m L

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= - 0.95 m L

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= - 0.65 m L

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Solution

The correct option is C $= - 0.75 m L$
The compressibility K is the reciprocal of the bulk modulus. : $Δ V = - V K Δ p$
$= - ((100 m L) \times 5 \times 10^{- 10} m^{2} / N) (15 \times 10^{6} N / m^{2})$
$= - 0.75 m L$
Hence the decrease in volume is 0.75mL

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Compressibility of water is 5×10−10m2/N. Find the decrease in volume of 100 mL of water when subjected to a pressure of 15 MPa.

The correct option is C =−0.75mL The compressibility K is the reciprocal of the bulk modulus. :ΔV=−VKΔp=−((100mL)×5×10−10m2/N)(15×106N/m2)=−0.75mLHence the decrease in volume is 0.75mL

Compressibility of water is $5 \times 10^{- 10} m^{2} / N .$ Find the decrease in volume of 100 mL of water when subjected to a pressure of 15 MPa.

The correct option is C $= - 0.75 m L$
The compressibility K is the reciprocal of the bulk modulus. : $Δ V = - V K Δ p$
$= - ((100 m L) \times 5 \times 10^{- 10} m^{2} / N) (15 \times 10^{6} N / m^{2})$
$= - 0.75 m L$
Hence the decrease in volume is 0.75mL