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Question

Compute (3m2n)3

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Solution

(3m2n)3
We know that (xy)3=x3y33xy(xy)
Here x=3m and y=2n we get
(3m2n)3
=(3m)3(2n)33(3m)(2n)(3m2n)
=27m38n312mn(3m2n)
=27m38n336m2+24mn2
=27m336m2n+24mn236n2

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