Compute:
$(4^{7})^{2} \times (4^{- 3})^{4}$

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Solution

$(4^{7})^{2} \times (4^{- 3})^{4}$
$= 4^{14} \times 4^{- 12}$
$= 4^{14 - 12}$
$= 4^{2}$
$= 16$

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