Compute and choose the relations that are correct.

$5 \times (8 + 10) = 10 \times (8 + 5)$

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$12 \times (6 - 3) = (12 \times 6) - (12 \times 3)$

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$(8 + 10) \times 15 > 8 + (10 \times 15)$

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$(- 11) \times (- 3) \times (2) = - 66$

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Solution

The correct options are
B
$12 \times (6 - 3) = (12 \times 6) - (12 \times 3)$

C
$(8 + 10) \times 15 > 8 + (10 \times 15)$

(A) $5 \times (8 + 10) = 5 \times 8 + 5 \times 10$
(using distributivity of multiplication over addition)

So, $5 \times (8 + 10) \neq 10 \times (8 + 5)$

(B) $12 \times (6 - 3) = (12 \times 6) - (12 \times 3)$

This is the correct law of distributivity of multiplication over subtraction.

(C) $(8 + 10) \times 15 > 8 + (10 \times 15)$

Here, $(8 + 10) \times 15 = 18 \times 15 = 270$
$8 + (10 \times 15) = 8 + 150 = 158$

So, this is correct.

(D) $(- 11) \times (- 3) \times (2)$

$= 11 \times 3 \times 2 = 66$

So, $(- 11) \times (- 3) \times (2) \neq - 66$

[When we multiply 2 negative numbers, we get a positive number. So, answer should be 66 instead of $(- 66)$ ]

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If A = {3, 6, 9, 12, 15, 18, 21}
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(2 \frac{1}{2} \times \frac{8}{10}) \div (1 \frac{1}{2} + \frac{5}{8})

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(v)

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Q. Which of the following dataset are organised?

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