Compute- 56280 - 253 -1625

As given ⇒(56/28)^0÷(2/5)^3×16/25 ∵(56/28)^0=1 ⇒ 1÷8/125×16/25 ⇒1/8/125×16/25 ⇒125/8×16/25 ⇒ 5×2=10 ...

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Byju's Answer

Standard X

Physics

Energy

Compute: 562...

Question

Compute:
$(\frac{56}{28})^{0} \div (\frac{2}{5})^{3} \times \frac{16}{25}$

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Solution

As given ${(\frac{56}{28})}^{0} \div {(\frac{2}{5})}^{3} \times \frac{16}{25}$
According to the BODMAS Rule:
(i) First preference is to simplify is the brackets expression:
So, ${(\frac{56}{28})}^{0} = 1$ as $a^{0} = 1$ and
${(\frac{2}{5})}^{3} = \frac{2^{3}}{5^{3}}$ [Since $(\frac{a}{b})^{m} = \frac{a^{m}}{b^{m}}$ ]
$∴ {(\frac{2}{5})}^{3} = \frac{8}{125}$
Thus, given expression can be rewrite as $1 \div \frac{8}{125} \times \frac{16}{25}$
(ii) The second preference is the division operation:
So, $\frac{1}{\frac{8}{125}} \times \frac{16}{25}$
$\Rightarrow \frac{125}{8} \times \frac{16}{25}$ [Final preference is multiplication ]
$\Rightarrow 5 \times 2 = 10$
Hence, the value of given expression is $10$ .

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Similar questions

Q. If

A = ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} \frac{2}{3} \frac{1}{3} \frac{7}{3} \end{matrix} \begin{matrix} 1 \frac{2}{3} 2 \end{matrix} \begin{matrix} \frac{5}{3} \frac{4}{3} \frac{2}{3} \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦

and

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, then compute

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\frac{5}{4} - \frac{7}{6} - \frac{- 2}{3}

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\frac{3}{8} - \frac{- 2}{9} + \frac{- 5}{36}

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Compute:(5628)0÷(25)3×1625

Compute:
$(\frac{56}{28})^{0} \div (\frac{2}{5})^{3} \times \frac{16}{25}$