∵ n!=n(n 1)(n 2)⋯2·1=n(n 1)! Now, 8!6!× 2!=8× 7× 6!6!× 2 × 1=28 ...

Compute 8!6!×...

Question

Compute $\frac{8!}{6! \times 2!}$

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Solution

$∵ n! = n (n - 1) (n - 2) \dots 2 \cdot 1 = n (n - 1)!$

Now,
$\frac{8!}{6! \times 2!} = \frac{8 \times 7 \times 6!}{6! \times 2 \times 1} = 28$

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Similar questions

Compute $\frac{8!}{6! \times 2!} .$

Q. If

A = ⎡ ⎢ ⎣ \begin{matrix} 2 & 0 & 4 6 & 2 & 8 2 & 4 & 6 \end{matrix} ⎤ ⎥ ⎦

and

B = ⎡ ⎢ ⎣ \begin{matrix} 8 & 4 & - 2 0 & - 2 & 0 2 & 2 & 6 \end{matrix} ⎤ ⎥ ⎦

.Compute

3 A + 2 B

A = ⎡ ⎢ ⎣ \begin{matrix} 2 & 0 & 4 6 & 2 & 8 2 & 4 & 6 \end{matrix} ⎤ ⎥ ⎦

and

B = ⎡ ⎢ ⎣ \begin{matrix} 8 & 4 & - 2 0 & - 2 & 0 2 & 2 & 6 \end{matrix} ⎤ ⎥ ⎦

Compute

A - B

A = ⎡ ⎢ ⎣ \begin{matrix} 2 & 0 & 4 6 & 2 & 8 2 & 4 & 6 \end{matrix} ⎤ ⎥ ⎦

and

B = ⎡ ⎢ ⎣ \begin{matrix} 8 & 4 & - 2 0 & - 2 & 0 2 & 2 & 6 \end{matrix} ⎤ ⎥ ⎦

Compute

A + B

Compute the following:
$(i i i) ⎡ ⎢ ⎣ \begin{matrix} - 1 & 4 & - 6 8 & 5 & 16 2 & 8 & 5 \end{matrix} ⎤ ⎥ ⎦ + ⎡ ⎢ ⎣ \begin{matrix} 12 & 7 & 6 8 & 0 & 5 3 & 2 & 4 \end{matrix} ⎤ ⎥ ⎦$

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Pascal Triangle

Standard XII Mathematics

Compute 8!6!×2!

∵n!=n(n−1)(n−2)⋯2⋅1=n(n−1)! Now, 8!6!×2!=8×7×6!6!×2×1=28

Compute $\frac{8!}{6! \times 2!}$

$∵ n! = n (n - 1) (n - 2) \dots 2 \cdot 1 = n (n - 1)!$

Now,
$\frac{8!}{6! \times 2!} = \frac{8 \times 7 \times 6!}{6! \times 2 \times 1} = 28$