Compute ${(\frac{64}{125})}^{1 / 3}$ .

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Solution

${(\frac{64}{125})}^{1 / 3} = {(\frac{4 \times 4 \times 4}{5 \times 5 \times 5})}^{1 / 3} = {(\frac{4^{3}}{5^{3}})}^{\frac{1}{3}}$

${(\frac{64}{125})}^{1 / 3} = \frac{4}{5}$

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Similar questions

2 \times (- 3)^{4} + (\sqrt[4]{3})^{0} \times (- 2)^{5} \div (64)^{\frac{2}{3}}

\sqrt{? + 483} \div 6 = 125^{1 / 3}

Find

$125^{\frac{1}{3}}$

{(- 3)}^{4} - {(\sqrt[4]{3})}^{o} \times {(- 2)}^{5} \div {(64)}^{\frac{2}{3}}

(27 \times 125)^{\frac{1}{3}}

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