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Question

Compute limx03x2xx

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Solution

3x2xx=2x((32)0+x1)x

=2x((32)0+x(32)0)x

Now,

limx02x((32)0+x(32)0)x

=limx0 2x limx0 ((32)0+x(32)0)x

=loge(32)

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