1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Compute Mean deviation about median for the following Frequency distribution.Variable(x)1015202530354045Frequency(f)73856849

A
10.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10.1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
13.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12.1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C 10.1Xi f c.f |Xi−M| fi×|Xi−M|10 7 7 20140 15 3 10 15 4520 8 18 10 8025 5 23 5 25 30 6 29 (Median Class) 0 0 35 8 37 5 40 40 4 41 10 40 45 9 50 15 135∑fi|Xi−M| =505Rank of median = N2th observation =25th (N2+1)th observation =26thMedian = 30+302 =30Mean Deviation about Median = 1N∑fi|Xi−M| = 50550Mean Deviation =10.1

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Mean of Grouped Data
STATISTICS
Watch in App
Explore more
Join BYJU'S Learning Program