Compute $P (A | B)$ if $P (B) = 0.5$ and $P (A \cap B) = 0.32$ .

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Solution

Given,
$P (B) = 0.5$

$P (A \cap B) = 0.32$

$P (A | B) = \frac{P (A \cap B)}{P (B)}$

$= \frac{0.32}{0.5} = 0.64$

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