Compute - -3 - i-3 - i-3-2

[(√(3) + i)(√(3) i)]^ 3/2 = (3 i^2)^ 3/2 = 4^ 3/2 = 18 ...

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Byju's Answer

Standard VIII

Mathematics

Finding Square of a Number Using Identity

Compute : [√...

Question

Compute :
$[(\sqrt{3} + i) (\sqrt{3} - i)]^{- 3 / 2}$

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Solution

$[(\sqrt{3} + i) (\sqrt{3} - i)]^{- 3 / 2} = (3 - i^{2})^{- 3 / 2} = 4^{- 3 / 2} = \frac{1}{8}$

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Compute :[(√3+i)(√3−i)]−3/2

[(√3+i)(√3−i)]−3/2=(3−i2)−3/2=4−3/2=18

Compute :
$[(\sqrt{3} + i) (\sqrt{3} - i)]^{- 3 / 2}$

$[(\sqrt{3} + i) (\sqrt{3} - i)]^{- 3 / 2} = (3 - i^{2})^{- 3 / 2} = 4^{- 3 / 2} = \frac{1}{8}$