Compute the area of the factory.

600 s q k m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

600 k m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

300 s q k m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

300 k m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $300 s q k m$
Length of the factory $(l) = 25 k m$
Width of the factory $(w) = 12 k m$

The given factory is in the shape of a rectangle.

The area of a rectangle $= l \times w$

Area $= 25 k m \times 12 k m$

Area $= 300 s q k m$

Hence, A is the correct option.

Suggest Corrections

Similar questions

In the figure, compute the area of the quadirlateral.

Compute the area of trapezium PQRS in the figure.

Q. Compute the area of the warehouse.

A computer producing factory has only two plants $T_{1}$ and $T_{2}$ . Plant $T_{1}$ produces 20% and plant $T_{2}$ produces 80% of the total computers produced. 7% of computers produced in the factory turn out to be defective. It is known that P(computer turns out to be defective, given that it is produced in plant $T_{1})$ = 10P (computer turns out to be defective, given that it is produced in plant $T_{2}$ ), where P(E) denotes the probability of an event E. A computer produced in the factory is randomly selected and it does not turn out to be defective. Then, the probability that it is produced in plant $T_{2}$ , is ?

Join BYJU'S Learning Program

Compute the area of the factory.

The correct option is C 300 sq kmLength of the factory (l)=25 km Width of the factory (w)=12 km The given factory is in the shape of a rectangle. The area of a rectangle =l×w Area =25 km×12 km Area =300 sq km Hence, A is the correct option.

The correct option is C $300 s q k m$
Length of the factory $(l) = 25 k m$
Width of the factory $(w) = 12 k m$

The given factory is in the shape of a rectangle.

The area of a rectangle $= l \times w$

Area $= 25 k m \times 12 k m$

Area $= 300 s q k m$

Hence, A is the correct option.