wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Compute the following:
(i) [abba]+[abba]
(ii) [a2+b2b2+c2a2+c2a2+b2]+[2ab2bc2ac2ab]
(iii) 1824586165+1283702654
(iv) [cos2xsin2xsin2xcos2x]+[sin2xcos2xcos2xsin2x]

Open in App
Solution

(i) [abba]+[abba]=[a+ab+bb+ba+a]=[2a2b02a]
(ii) [a2+b2b2+c2a2+c2a2+b2]+[2ab2bc2ac2ab]
=[a2+b2+2abb2+c2+2bca2+c22aca2+b22ab]
=[(a+b)2(b+c)2(ac)2(ab)2]
(iii) 1824586165+1283702654
=1+128+82+34+75+08+26+616+55+4
=11165115100219
(iv) [cos2xsin2xsin2xcos2x]+[sin2xcos2xcos2xsin2x]
=[1111](sin2x+cos2x=1)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Adjoint and Inverse of a Matrix
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon