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Question

Compute the following:
(iv)[cos2xsin2xsin2xcos2x]+[sin2xcos2xcos2xsin2x]

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Solution

[cos2xsin2xsin2xcos2x]+[sin2xcos2xcos2xsin2x]=[cos2x+sin2xsin2x+cos2xsin2x+cos2xcos2x+sin2x]=[1111][sin2x+cos2x=1]


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