Compute the following: (iv)[cos2xsin2xsin2xcos2x]+[sin2xcos2xcos2xsin2x]
[cos2xsin2xsin2xcos2x]+[sin2xcos2xcos2xsin2x]=[cos2x+sin2xsin2x+cos2xsin2x+cos2xcos2x+sin2x]=[1111][∵sin2x+cos2x=1]