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Standard XII

Physics

Work

Compute the h...

Question

Compute the heat added, the work done, and the change in internal energy if this is done at constant pressure.

Δ Q = 280800 J

;

Δ W = 81000 J

;

Δ U = 199800 J

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Δ Q = 280000 J

;

Δ W = 81000 J

;

Δ U = 199800 J

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Δ Q = 280800 J

;

Δ W = 81000 J

;

Δ U = 199900 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Δ Q = 280000 J

;

Δ W = 81000 J

;

Δ U = 199900 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is A $Δ Q = 280800 J$ ; $Δ W = 81000 J$ ; $Δ U = 199800 J$
$Δ Q = Δ U + Δ W$
$Δ U = n C_{v} Δ T$
Since $C_{v}$ is given in terms of $J k g^{- 1} L - 1$ ,
$Δ U = 3 \times C_{v} Δ T = 3 \times 740 \times (100 - 10) = 199800 J$
Calculation of $Δ W$
Since P is constant, $Δ W = P (V_{2} - V_{1}) = n R (T_{2} - T_{1}) = \frac{3000}{28}$ $\times 8.4 \times (100 - 10) = 81000 J$
Calculation of $Δ Q$
$Δ Q = Δ U + Δ W = 199800 + 81000 = 280800 J$

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Similar questions

Q. Match the thermodynamic processes taking place in a system with the correct conditions.
In the table,

Δ Q

is the heat supplied,

Δ W

is the work done and

Δ U

is the change in internal energy of the system.

Process	Condition
(i) Adiabatic	(A) $Δ W = 0$
(ii) Isothermal	(B) $Δ Q = 0$
(iii) Isochoric	(C) $Δ U \neq 0$ , $Δ W \neq 0$ , $Δ Q \neq 0$
(iv) Isobaric	(D) $Δ U = 0$

Q. Let

Δ U_{1}

and

Δ U_{2}

be the change in internal energy in process A and B respectively,

Δ Q

be the net heat given to the system in process (A+B) and

Δ W

be the net work done by the system in the process (A+ B).
i)

Δ U_{1} + Δ U_{2} = 0

ii)

Δ U_{1} - Δ U_{2} = 0

iii)

Δ Q + Δ W = 0

iv)

Δ Q + Δ W = 0

Q. Refer to figure. Let ∆U₁ and ∆U₂ be the change in internal energy in processes A and B respectively, ∆Q be the net heat given to the system in process A + B and ∆W be the net work done by the system in the process A + B.

(a) ∆U₁ + ∆U₂ = 0.
(b) ∆U₁ − ∆U₂ = 0.
(c) ∆Q − ∆W = 0.
(d) ∆Q + ∆W = 0

Q. An ideal gas undergoes the process

1 ⟶ 2

as shown in the figure, the heat supplied and work done in process is

Δ Q

and

Δ W

respectively. the ratio

Δ Q : Δ W

Q. The figures given below show different processes (relating pressure

P

and volume

V

) for a given amount for an ideal gas.

Δ W

is work done by the gas and

Δ Q

is heat absorbed by the gas.

\begin{matrix} Column I & Column II 1. In Fig (i) & (p) Δ Q > 0 2. In Fig (i i) & (q) Δ W < 0 3. In Fig (i i i) & (r) Δ Q < 0 4. In Fig (i v) & (s) Δ W > 0 \end{matrix}

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