Question

Compute the heat generated while transferring $96000\mathrm{coulombs}$ of charge in $1\mathrm{hour}$ through a potential difference of $50\mathrm{V}$.

Answer 1

Step 1: Given information

Charge, $\mathrm{Q}=96000\mathrm{C}$

Time, $$\begin{gathered} \mathrm{t}=1\mathrm{hr} \\ =60\times 60 \\ =3600\mathrm{s} \end{gathered}$$

Potential difference, $\mathrm{V}=50\mathrm{V}$

Step 2: Finding the current

We know the formula,

Current,

$\mathrm{I}=\frac{\mathrm{Q}}{\mathrm{t}}$

By substituting the values, we get

$$\begin{gathered} =\frac{96000}{3600} \\ =\frac{80}{3}\mathrm{A} \end{gathered}$$

Step 3: Finding the heat generated

The quantity of heat generated will be:

$\mathrm{H}=\mathrm{V}\times \mathrm{I}\times \mathrm{t}$

By substituting the values,

$$\begin{gathered} =50\times \frac{80}{3}\times 3600 \\ =4.8\times {10}^6\mathrm{J} \end{gathered}$$

Therefore, the heat generated is $4.8\times {10}^6\mathrm{J}$.