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Question

Compute the mean deviation from the median of the following distribution :

Class0101020203030404050Frequency51020510

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Solution

ClassFrequencyfiCumulative frequencyMid-values xi|di|=|xi25|fi|di|010555201001020101515101002030203525003040540351050405010504520200N=5i=1fi=505i=1fi|di|=450

Here, N = 50

N2=25

The cumulative frequency greater than N2=25 is 35 and the corresponding class is 20 -30.

Therefore the median class is 20 - 30.

l=20,f=20,F=15,N=50,h=10

Median =l+(N2F)f×h

=20+(50215)20×=20+(2515)20×10=25

Mean deviation from the median =5i=1fi|di|N=45050=9


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