Compute the mode from the following data:
Classinterval1−56−1011−1516−2021−2526−3031−3536−4041−4546−50Frequency381318282013864
The given series is converted from inclusive to exclusive form and on preparing the frequency table, we get
Class | Frequency |
0.5-5.5 | 3 |
5.5-10.5 | 8 |
10.5-15.5 | 13 |
15.5-20.5 | 18 |
20.5-25.5 | 28 |
25.5-30.5 | 20 |
30.5-35.5 | 13 |
35.5-40.5 | 8 |
40.5-45.5 | 6 |
45.5-50.5 | 3 |
As the class 20.5-25.5 has a maximum frequency, so it is the modal class:
Therefore,
l=20.5, h=5, f=28 and f1=18 and f2=20
Mode = l+[h×(f−f1)/(2f−f1−f2)]
=20.5+[5×(28−18)/(2×56−18−20)]
= 20.5 + [5 x 10 /18]
= 20.5 + 2.78 = 23.28
Hence, mode = 23.28