Question

Compute the quotient using the tape model.

• A. 3
• B. 2
• C. 4
• D. 6

Answer 1

The correct option is B 2

In the first model, six $\frac{1}{9}$ are there.

In the second model, one $\frac{1}{3}$ is there.

As three $\frac{1}{9}$ is equal to one $\frac{1}{3}$.

So, the number of $\frac{1}{3}$ in $\frac{6}{9}$ is 2.

i.e. $\frac{6}{9}÷\frac{1}{3}$ = 2

Hence, two $\frac{1}{3}$ are there.