Compute the value of $19^{2} + 11^{2}$

= $462$

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= $472$

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= $482$

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= $492$

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Solution

The correct option is C
= $482$

The given expression is

$19^{2} + 11^{2}$

= $(19 + 11)^{2} - 2 \times 19 \times 11$ [ $a^{2} + b^{2} = (a + b)^{2} - 2 \times a \times b$ ]

= $(30)^{2} - 418$

= $900 - 418$

= $482$

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