Compute the value of $24^{2} + 20^{2}$

$974$

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$986$

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$926$

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$976$

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Solution

The correct option is D
$976$

The given expression is

$24^{2} + 20^{2}$

$= (22 + 2)^{2} + (22 - 2)^{2}$

$= 2 (22^{2} + 2^{2}) [(x + y)^{2} + (x - y)^{2} = 2 (x^{2} + y^{2})]$

$= 2 (484 + 4)$

$= 2 \times 488$

$= 976$

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The value of $24^{2}$ is equal to

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