Compute the value of 4 3-4 2 - 2 1-4 2

The given expression is (4 3/4 )^2 (2 1/4 )^2 which is equal to (4 3/4 21/4 )(4 3/4 + 21/4 ) [a^2 b^2 = (a+b)(a b) ] = 21/2× 7 = 14 1/2 ...

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Standard VIII

Mathematics

Factorisation by Regrouping Terms

Compute the v...

Question

Compute the value of ${(4 \frac{3}{4})}^{2} - {(2 \frac{1}{4})}^{2}$

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Solution

The given expression is

${(4 \frac{3}{4})}^{2} - {(2 \frac{1}{4})}^{2}$ which is equal to

$(4 \frac{3}{4} - 2 \frac{1}{4}) (4 \frac{3}{4} + 2 \frac{1}{4}) [a^{2} - b^{2} = (a + b) (a - b)]$

$= 2 \frac{1}{2} \times 7$

$= 14 \frac{1}{2}$

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Compute the value of (434)2−(214)2

The given expression is (434)2−(214)2 which is equal to (434−214)(434+214) [a2−b2=(a+b)(a−b)] =212×7 =1412

Compute the value of ${(4 \frac{3}{4})}^{2} - {(2 \frac{1}{4})}^{2}$

The given expression is

${(4 \frac{3}{4})}^{2} - {(2 \frac{1}{4})}^{2}$ which is equal to

$(4 \frac{3}{4} - 2 \frac{1}{4}) (4 \frac{3}{4} + 2 \frac{1}{4}) [a^{2} - b^{2} = (a + b) (a - b)]$

$= 2 \frac{1}{2} \times 7$

$= 14 \frac{1}{2}$