Conc. $H_{2} S O_{4}$ in addition to dry $K N O_{3}$ gives brown fumes of :

S O_{2}

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S O_{3}

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N O

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N O_{2}

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Solution

The correct option is D $N O_{2}$
Conc. $H_{2} S O_{4}$ on addition to dry $K N O_{3}$ gives brown fumes of $N O_{2}$ .
$K N O_{3} + H_{2} S O_{4} ⟶ K H S O_{4} + H N O_{3}$
$\begin{matrix} 4 H N O_{3} ⟶ 2 H_{2} O + 4 N O_{2} + O_{2} (B r o w n) \end{matrix}$

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