Conc. $H_{2} S O_{4}$ reacts with carbon and forms:

C O_{2}

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S O_{2}

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H_{2} C O_{3}

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H_{2} S O_{3}

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Solution

The correct options are
A $C O_{2}$
B $S O_{2}$
Conc. $H_{2} S O_{4}$ reacts with carbon and forms $C O_{2}$ and $S O_{2}$ .
$C + 2 H_{2} S O_{4} \to C O_{2} ↑ + 2 S O_{2} ↑ + 2 H_{2} O$
$H_{2} S O_{4}$ is reduced to $S O_{2}$ and $C$ is oxidised to $C O_{2}$ .

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